X^2+x=129

Solution for X^2+x=129 equation:

X^2+X=129

We move all terms to the left:

X^2+X-(129)=0

a = 1; b = 1; c = -129;
Δ = b2-4ac
Δ = 12-4·1·(-129)
Δ = 517
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$X_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$X_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$X_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(1)-\sqrt{517}}{2*1}=\frac{-1-\sqrt{517}}{2}
$
$X_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(1)+\sqrt{517}}{2*1}=\frac{-1+\sqrt{517}}{2}
$